Example

Hello world

\[ ax^2 + bx + c = 0\\ \]

Let \(\gamma = x-b/2a\) and substitute back:

\[ \begin{align} a\left(\gamma+\frac{b}{2a}\right)^2 + b\left(\gamma+\frac{b}{2a}\right) + c &=0 \\ a\left(\gamma^2 + \frac{b\gamma}{a} + \frac{b^2}{4ac}\right) + b\left(\gamma + \frac{b}{2a}\right) + c &= 0\\ a\gamma^2 + (2b)\gamma + \frac{b^2}{4c} + \frac{b}{4a} &= 0 \end{align} \]